Using car tires as a flywheel
@anris and i are thinking about making the shredder human powered, and it would be a huge improvement to have a flywheel, flywheels are unfortunately rather difficult to come by here in Denmark. this is why we were thinking about using a car tire as a flywheel. does anyone have a formula to calculate the angular momentum of a given tyre and wheel?
We got the idea efter some correspondance in this topic about powering the shredder with your hands:
By adding a flywheel and some gears, the momentum from the flywheel should be enough to shred the plastic.
The desired flywheel; an old wheel made from casted iron (these are the ones that are hard to come by)
A drawing of the hand powered shredder we have in mind
Red = Gears from a bike
Green = The chain from a bike
Yellow = The handle
Pink = The flywheel with 12 – 20 kg, to create momentum
Blue = axis
Light blue = Plastic
What we are trying to figure out; if we want to use a tire from a car or a bike, with or without added weights
A bit more info can be found on the “Hand cranked shredder”-topic but this is the short lines.
Can anyone help us out with some calculations or guidance to what kind of flywheel that is the best? 🙂
here are some posts from a bike powered shredder thread that i posted to:
Well there are a few governing equations to sizing flywheels for this application
there are a few variables that are listed bellow:
1. Material that is being cut properties
2. Material that is being cut cross section
3. Flywheel design
4. Flywheel Material
So onto the equations:
First rotational kinetic energy units (Joules)
I = rotational inertia (moment of inertia) has to do with flywheel design
W = angular velocity
to find I just design a flywheel in a standard cad program and it will usually tell you what it is at center of mass
W is found by taking the tangential velocity on the outer rim of the flywheel and dividing it by the radius of the flywheel W = v/r
Next value that is important is the Tensile Impact Strength value of the material.
This is looked up from a table of your material for HDPE it is around 243KJ/m^2
i designed this bowl on cad (not designed for flywheel)
and looked up its highest moment of inertia on cad which = .0004647 Kg m^2
r = .109
i need to find how fast i must rotate the flywheel to cut the material
impact strength of HDPE of 243KJ/m^2
and a cutting cross section of 1 inch x 1 inch or .00064516 m^2
impact strength needed is 243,000 * .00064516 = 156.77388 Joules of KE needed
so solving KE equation for velocity
1/2(W^2)(I)=KE W= V/r 1/2(V^2/r^2)(I)=KE ((KE(r^2)(2))/I)^(1/2) =V
((156.77388(.109^2)(2))/(.0004647)))^(1/2) = 89 m/s or 200 mph lolz
a more important problem would be to solve for I as most people can pedal at 10mph
because you are solving for I you can determine what you need to model and using what material
to solve for I
however as you see you would also need to know the radius of your part as well so this equation has 2 unkowns.
basically the r would be limited by the machine that you are going to use to make the flywheel or the material you can get your hands on
you would then design around that.
I did some of the math for a 20Kg cast iron lifting plate
that would get you pretty close to cutting that 1 inch by 1 inch cross section
however that is only 1 tooth so you would need a 20kg plate per tooth /2
so if you have 12 i would do 6-8 20kg plates so 160kg of weight for flywheel.
reason why you would need a plate per tooth is that your flywheel would stop after only one tooth cut but you want to keep going indefinitely so you will need to have energy to spare so that you just spend energy keeping the flywheel up to speed.
so a 20kg cast iron lifting plate would be a good idea.
the thread could be found here: https://davehakkens.nl/community/forums/topic/bicycle-shredder-costs-work-in-progress/
Why dont you try this
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